CGPSC 2025 Paper 2 part5 (CSAT) Questions with Solutions (Part 5)

CGPSC 2025 Paper 2 (CSAT) Questions with Solutions (Part 5)

Q36. Shreni (Series) 24, 21, 18, ... ke kitne padon (terms) ka yog (sum) 78 hoga?

(A) 5 ya 12

(B) 7 ya 14

(D) 6 ya 10

Answer: (C) 4 ya 13

Solution: Yeh ek Samantar Shredi (Arithmetic Progression - AP) hai jahan pehla pad a = 24 aur sarvantar (common difference) d = 21 - 24 = -3 hai. Formula: S_n = \frac{n}{2} [2a + (n-1)d] 78 = \frac{n}{2} [2(24) + (n-1)(-3)] 156 = n [48 - 3n + 3] \implies 156 = n [51 - 3n] 156 = 51n - 3n^2 \implies 3n^2 - 51n + 156 = 0 3 se bhaag dene par: n^2 - 17n + 52 = 0 Iske gunankhand (factors) karne par: (n-4)(n-13) = 0 \implies n = 4 \text{ ya } 13. (Note: 4 padon ka yog bhi 78 hai, aur aage ke pad minus me hone ke karan 13 padon ka yog bhi 78 hi aata hai).

Q37. Triangle Properties: Tribhuj (Triangle) ABC me AB = 6\sqrt{3}\text{ cm}, AC = 12\text{ cm} tatha BC = 6\text{ cm} hai, tab kon (Angle) B ka maan hai:

(A) 120^\circ

(B) 60^\circ

(D) 90^\circ

Answer: (D) 90^\circ

Solution: Sabhi bhujaon ka varg (square) karke dekhte hain: AB^2 = (6\sqrt{3})^2 = 36 \times 3 = 108 BC^2 = 6^2 = 36 AC^2 = 12^2 = 144 Yahan, AB^2 + BC^2 = 108 + 36 = 144 = AC^2. Kyunki yeh Pythagoras pramey (Aadhar^2 + Lamb^2 = Karn^2) ko santusht karta hai, isliye yeh ek Samkon Tribhuj (Right-angled triangle) hai aur sabse badi bhuja AC (Karn) ke saamne wala kon \angle B = 90^\circ hoga.

Q38. Ek parivar me, paanch logon ke samooh me K, L aur M mahatvakankshi (ambitious) hain. M, N aur R imandar (honest) hain; L, M aur N buddhiman (intelligent) hain aur K, N va R mehnati (industrious) hain. Is samooh me se 'na toh mehnati aur na hi mahatvakankshi' vyakti hai:

(A) Keval K

(B) L aur R

(D) Samooh me koi nahi

Answer: (D) Samooh me koi nahi

Solution: Sawaal ke anusar sabhi vyaktiyon ki khoobiyaan dekhein:
- K \rightarrow Mahatvakankshi, Mehnati
- L \rightarrow Mahatvakankshi, Buddhiman
- M \rightarrow Mahatvakankshi, Imandar, Buddhiman
- N \rightarrow Imandar, Buddhiman, Mehnati
- R \rightarrow Imandar, Mehnati Hume aisa vyakti chahiye jo na toh Mehnati (K, N, R nahi ho sakta) ho aur na hi Mahatvakankshi (K, L, M nahi ho sakta). Bache hue vyaktiyon me se koi aisa nahi hai jo dono me na ho, isliye answer Samooh me koi nahi hoga.
Q39. Profit & Loss: Kisi saaman ko ek nishchit moolya par vikray (sell) karne par ek vyakti ko 10% ka laabh (profit) hota hai. Usi saaman ko dogune moolya (double price) par vikray karne par use kitna pratishat laabh hoga?

(A) 20%

(B) 100%

(C) 120%

(D) 140%
- Answer: (C) 120%
- Solution: Mano saaman ka kray moolya (Cost Price - CP) = 100. 10% laabh par vikray moolya (Selling Price - SP) = 110. Naya vikray moolya (Doguna) = 110 \times 2 = 220. Naya laabh = 220 - 100 = 120. Pratishat laabh = \frac{120}{100} \times 100 = 120\%.
CGPSC 2025 Chhattisgarhi & Hindi Language Questions

Q40. Chhattisgarh rajbhasha aayog dwara Chhattisgarhi ke maanikaran (standardization) ke liye 22 July 2018 ko rajyastariya sangoshthi ka aayojan kahan kiya gaya tha?

(A) Bilaspur

(B) Ambikapur

(C) Jagdalpur

(D) Rajnandgaon
- Answer: (A) Bilaspur
Q40. Paut + An = Paavan (पौ + अन = पावन) me kaun si sandhi hai?

(A) Deergh svar sandhi

(B) Gun svar sandhi

(C) Vriddhi svar sandhi

(D) Ayaadi svar sandhi
- Answer: (D) Ayaadi svar sandhi
- Solution: Jab औ + अ milkar 'आव' (Aav) bante hain, toh vahan Ayaadi Svar Sandhi hoti hai.
Q42. 'Nisaan' (निसान) ka paryayvachi (synonym) nahi hai:

(A) Nagada (नगाड़ा)

(B) Dundubhi (दुन्दुभि)

(C) Mridang (मृदंग)

(D) Jhanda (झंडा)
- Answer: (D) Jhanda (झंडा)
- Note: Chhattisgarhi aur purani Hindi me 'निसान' ka prayog baaje/nagade ke roop me kiya jata hai, isliye 'Jhanda' iska sahi paryayvachi nahi hai.
Important Message for Aspirants: CGPSC Prelims Paper 2 (CSAT) ke questions ko solve karte samay hamesha Chhattisgarhi aur Hindi bhasha ke section ko pehle hal karein kyunki yeh kam samay me zyada score dete hain. Iske baad hi Maths aur Reasoning ke lambe sawalon par jayein.