CGPSC 
2025 Paper 2 (CSAT) Questions with Solutions (Part 4)
Q29. Di gayi shreni (Series) me lupt pad (?) ke liye sahi vikalp chuniye:
PRS, TWY, XBE, BGK, ?
(A) FLQ
(B) ELP
(C) ELQ
(D) FLP
- Answer: (C) ELQ
- Solution: Is shreni me pratyek pad ke aksharon (letters) ka pattern is prakar hai:
- Pehla akshar: P \xrightarrow{+4} T \xrightarrow{+4} X \xrightarrow{+4} B \xrightarrow{+4} \mathbf{E}
- Doosra akshar: R \xrightarrow{+5} W \xrightarrow{+5} B \xrightarrow{+5} G \xrightarrow{+5} \mathbf{L}
- Teesra akshar: S \xrightarrow{+6} Y \xrightarrow{+6} E \xrightarrow{+6} K \xrightarrow{+6} \mathbf{Q}
- Is prakar agla pad ELQ hoga.
hoga.
Q30. Blood Relation: Diya gaya hai ki:
- P, Q ki maa hai.
- R, P ka beta hai.
- S, T ka bhai hai.
- T, Q ki beti hai. Tab S ki dadi (Grandmother) kaun hai? (A) P (B) Q (C) R (D) T
- Answer: (A) P
- Solution: Kathan ke anusar rishton ka chitra is prakar banta hai:
- T, Q ki beti hai aur S, T ka bhai hai, iska matlab S aur T dono Q ke bachhe hain.
- P, Q ki maa hai.
- Kyunki P, Q ki maa hai aur Q ke bachhe S aur T hain, isliye S ki dadi/nani P hogi
Q31. Venn Diagram: Adhiktar gitarvaadak (guitarists) dadhi wale purush hote hain. Yadi A sabhi purushon ke samuchchay (set) ko, B dadhi wale purushon ke samuchchay ko aur C sabhi purush gitarvaadakon ke samuchchay ko nirupit karta hai, toh sahi aarekha (diagram) hoga:
(Aap apne blog par options me diye gaye gol aakritiyon wale Venn diagram ka sandarbh de sakte hain).
- Answer: (A)
- Solution: Kyunki B (dadhi wale purush) aur C (purush gitarvaadak) dono poori tarah se purush hain, isliye B aur C dono ka gola A (sabhi purush) ke bade gole ke andar aayega. Saath hi, "adhiktar gitarvaadak dadhi wale hote hain" iska matlab B aur C ke gole aapas me ek-doosre ko kaatenge (overlap karenge). Yeh sthiti aarekha (A) me sahi darshayi gayi hai.
Q32. Yadi a, b, c, d aur e ka madhya (mean) 28 hai tatha a, c aur e ka madhya 24 hai, tab b aur d ka madhya hai:
(A) 31
(B) 32
(C) 34
(D) 33
- Answer: (C) 34
- Solution: Five terms ka kul yog: a + b + c + d + e = 28 \times 5 = 140. Three terms ka kul yog: a + c + e = 24 \times 3 = 72. Ab, b aur d ka yog nikalne ke liye: (a + b + c + d + e) - (a + c + e) = 140 - 72 \implies b + d = 68. b aur d ka madhya (mean) = \frac{b+d}{2} = \frac{68}{2} = 34.
Q33. Communication & Interpersonal Skills: Ek shrota (listener), vishay (subject) ke bajay vakta (speaker) ki dikhavat aur prastuti shaili (appearance & delivery style) par dhyan kendrit kar raha hai. Is maamle me sunne me badha (barrier to listening) hai:
(A) Nishkarsh par pahunchma (Jumping to conclusion)
(B) Vishay ke baare me pehle se hi nirnay lena (Prejudging the subject)
( C) Keval tathya ekatrit karna (Gathering only the facts)
(D) Galat focus (Wrong focus)
- Answer: (D) Galat focus (Wrong focus)
- Solution: Jab koi shrota mukhya vishay ya sandesh ko chhodkar vakta ke kapde, dikhavat ya bolne ke tareeke par dhyan dene lagta hai, toh use sanchar me Wrong Focus (Galat focus) ki badha mana jata hai.
CGPSC 2025 Chhattisgarhi & Hindi Vyakaran Questions
Q34. Kis vaakya (sentence) me prachisheshan (प्रविशेषण) hai?
(A) वोह लड़की आय। (Voh ladki aay.)
(B) वोह सुघ्यर लड़की आय। (Voh sughyar ladki aay.)
(C) वोह बहुतेच सुघ्घर लड़की आय। (Voh bahutéch sughghar ladki aay.)
(D) Uprokt me se koi nahi
- Answer: (C) वोह बहुतेच सुघ्घर लड़की आय।
- Solution: Jo shabd visheshan (adjective) ki bhi visheshata batata hai use pravisheshan kehte hain. Yahan 'सुघ्घर' (sundar) ek visheshan hai aur uski visheshata 'बहुतेच' (bahut zyada) shabd bata raha hai.
Q35. 'कांसा के थारी' (Kansa ke thari) me kaun sa kaarak (कारक) hai?
(A) Adhikaran (अधिकरण)
(B) Apadaan (अपादान)
(C) Karan (करण)
(D) Sambandh (संबंध)
- Answer: (D) Sambandh (संबंध)
- Solution: Hindi vyakaran ke 'का/के/की' ki tarah Chhattisgarhi me bhed darshane ya sambandh batane ke liye 'के' ka prayog hota hai, jo Sambandh Kaarak ko darshata hai.
- CGPSC CSAT me pass hone ke liye kitne percent chahiye? (33% for General, 23% for Reserved categories).
- Kya CSAT ke number merit me judte hain? (Nahi, yeh keval qualifying hota hai).
 Questions with Solutions (Part 4)){kind=link}
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