CGPSC 2025 Paper 2 (CSAT) Questions with Solutions (Part 2)

Q9. Sanchar-prakriya (Communication Process) me jaanboojhkar soochna me her-pher karna kahlata hai:

(A) Chhanan (Filtering)

(B) Aagrahita (Assertiveness)

(D) Amoortata (Abstraction)

Answer: (A) Chhanan (Filtering)

Solution: Sanchar me jab sender soochna ko jaanboojhkar is tarah badalta ya her-pher karta hai taaki vah receiver ko pasand aaye, toh use Filtering khte hain.

Q10. A, P, R, X, S aur Z ek pankti (row) me baithe hain. S aur Z kendra (centre) me hain tatha A aur P chhor (ends) par hain. R, A ke bai n (left) or baitha hai, toh P ke dai n (right) or kaun baitha hai?

(A) A

(B) S

(D) Z

Answer: (C) X

Solution: Sabhi ka mukh uttar ki or manne par: A aur P chhor par hain, aur R, A ke bai n or baitha hai, iska matlab A daini chhor par nahi ho sakta (kyunki uske bai n or jagah chahiye). Isliye, A bai n chhor par hai aur P daini chhor par hai. Kram is tarah banega: R - A - (S, Z) - X - P. Isliye P ke daini or (agar pankti ka ant hai toh uske pados me) bacha hua vyakti X baitha hai.

Q11. Dono aarohi kramit sankhyayein (ascending series): 63, 65, 67, ... aur 3, 10, 17, ... ke kaun-se pad (term) ka maan saman hoga?

(A) 12

(B) 13

(D) 15

Answer: (B) 13

Solution: Pehli AP: a_1 = 63, d_1 = 2. n-va pad = 63 + (n-1)2. Doosri AP: a_2 = 3, d_2 = 7. n-va pad = 3 + (n-1)7. Dono ko barabar karne par: 63 + 2n - 2 = 3 + 7n - 7 \implies 61 + 2n = 7n - 4 5n = 65 \implies n = 13.

Q12. Ek seminar me Angrezi, Urdu evam Sanskrit me pratibhagiyon ki sankhya kramshah 45, 75 evam 135 hai. Unhe samayojit karne ke liye aavashyak kamron ki kam se kam sankhya kya hogi, yadi pratyek kamre me pratibhagiyon ki sankhya tatha bhasha saman ho?

(A) 17

(B) 255

(D) 135

Answer: (A) 17

Solution: Sabse pehle 45, 75, aur 135 ka HCF (Mahattam Samapavartak) nikalenge, jo ki 15 aayega. Yani ek kamre me adhiktam 15 log baith sakte hain. Kamron ki sankhya = \frac{45}{15} + \frac{75}{15} + \frac{135}{15} = 3 + 5 + 9 = 17.

Q13. Yadi (x - 1), 4x^3 + 3x^2 - 4x + k ka ek gunankhand (factor) hai, toh k ka maan hai:

(A) 3

(B) 4

(D) -4

Answer: (C) -3

Solution: Factor Theorem ke anusar, yadi (x - 1) ek factor hai, toh x = 1 rakhne par samikaran ka maan 0 hona chahiye. 4(1)^3 + 3(1)^2 - 4(1) + k = 0 4 + 3 - 4 + k = 0 \implies 3 + k = 0 \implies k = -3.

Q14. Ek parivar me pati-patni, unke teen bete, do betiyan aur teen beton ki teen patniyan hain. Parivar me mahilaon (women) ki kul sankhya hai:

(A) 5

(B) 6

(D) 10

Answer: (C) 7

Solution: Parivar me mahilaon ki ginti: 1 (Patni) + 2 (Betiyan) + 3 (Beton ki patniyan) = 7 mahilayein.

Q15. 4 paise, ek rupaye ka kitne pratishat (percentage) hai?

(A) 4%

(B) 0.4%

(D) 40%

Answer: (A) 4%

Solution: 1 Rupya = 100 paise. Pratishat = \frac{4}{100} \times 100 = 4\%.

CGPSC 2025 Hindi & Chhattisgarhi Bhasha (Language) Questions

Blogger blog par language section se kaafi traffic aata hai, isliye in questions ko dhyan se dekhein:

Q16. 'Chatvari' (चत्वारि) ka Hindi tadbhav roop hoga:

(A) Chatari (चतारि)

(B) Chaturth (चतुर्थ)

(D) Chatvar (चत्वार)

Answer: (C) Chaar (चार)

Q17. Apne kiye huye upkar ko yaad rakhne/manne wala vyakti:

(A) Kritaghna (कृतघ्न)

(B) Kritagya (कृतज्ञ)

(D) Kreet (क्रीत)

Answer: (B) Kritagya (कृतज्ञ)

Note: Upkar na manne wale ko Kritaghna kehte hain.

Q18. Chhattisgarhi muhavra "Gari Bandhna" (गरी बांधना) ka kya arth hai?

(A) Ghamand todna

(B) Yaad rakhna

(D) Vivah karna

Answer: (B) Yaad rakhna

Q19. 'Pyaj' (प्याज) ko Chhattisgarhi me kya kehte hain?

(A) Tuma (तुमा)

(B) Patal (पताल)

(D) Gondli (गोंदली)

Answer: (D) Gondli (गोंदली)

Q20. 'Kudukh' (कुडुख) boli kis janjati (tribe) ke log bolte hain?

(A) Oraon (उरांव)

(B) Muria (मुरिया)

(D) Abujhmadia (अबूझमाड़िया)

Answer: (A) Oraon (उरांव)
Aapko CGPSC CSAT ke kis topic me sabse jyada dikkat hoti hai? Hame niche comment me batayein!"

CGPSC 2025 Paper 2 (CSAT) Questions with Solutions (Part 2)